1/3(9k-6)=7

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Solution for 1/3(9k-6)=7 equation: 


k in (-oo:+oo)

(1/3)*(9*k-6) = 7 // - 7

(1/3)*(9*k-6)-7 = 0

1/3*(9*k-6)-7 = 0

1/3*(9*k-6)-7 = 0

3*k-9 = 0

3*k-9 = 0

3*k-9 = 0 // + 9

3*k = 9 // : 3

k = 9/3

k = 3

k = 3

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