1/3(9p-12)-0.5(16p-10)=-16

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Solution for 1/3(9p-12)-0.5(16p-10)=-16 equation: 



1/3(9p-12)-0.5(16p-10)=-16

We move all terms to the left:

1/3(9p-12)-0.5(16p-10)-(-16)=0



Domain of the equation: 3(9p-12)!=0

p∈R



We add all the numbers together, and all the variables

1/3(9p-12)-0.5(16p-10)+16=0

We multiply parentheses

1/3(9p-12)-8p+5+16=0

We multiply all the terms by the denominator


-8p*3(9p-12)+5*3(9p-12)+16*3(9p-12)+1=0

Wy multiply elements

-24p^2(9+15p(9+48p(9+1=0

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