1/3(9t+3)=3t+1

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Solution for 1/3(9t+3)=3t+1 equation: 


t in (-oo:+oo)

(1/3)*(9*t+3) = 3*t+1 // - 3*t+1

(1/3)*(9*t+3)-(3*t)-1 = 0

(1/3)*(9*t+3)-3*t-1 = 0

1/3*(9*t+3)-3*t-1 = 0

1/3*(9*t+3)-3*t-1 = 0

1-1 = 0

0 = 0

0 = 0

t belongs to the empty set

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