1/3(9t-6)=2t+8

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Solution for 1/3(9t-6)=2t+8 equation:



1/3(9t-6)=2t+8
We move all terms to the left:
1/3(9t-6)-(2t+8)=0
Domain of the equation: 3(9t-6)!=0
t∈R
We get rid of parentheses
1/3(9t-6)-2t-8=0
We multiply all the terms by the denominator
-2t*3(9t-6)-8*3(9t-6)+1=0
Wy multiply elements
-6t^2(9-24t(9+1=0

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