If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(1/3)*(9*x+1) = 3*x+1 // - 3*x+1
(1/3)*(9*x+1)-(3*x)-1 = 0
(1/3)*(9*x+1)-3*x-1 = 0
1/3*(9*x+1)-3*x-1 = 0
1/3*(9*x+1)-3*x-1 = 0
1/3-1 = 0
-2/3 = 0
-2/3 = 0
-2/3 = 0 // * 3
-2 = 0
x belongs to the empty set
| -12=m/19 | | W5/w9 | | 3x+27=3 | | 0.28x=2.52 | | x/5=-1.1/10 | | 2(45-16)-5s=-5 | | .3k+0.5k+13=1 | | -6x-28=2x | | 480/200 | | -6(-5v)=54 | | 5x-5(x-3)+x= | | 4/1+2*1 | | 4(9-2)+6/15 | | x/5=-11/10 | | -8=-y+4 | | 10+30y=-30 | | x-32=55 | | 4t-8=-20 | | 6x=(7x+24) | | m-10=-13 | | 200/480 | | 9n+4=8+5n | | (3/7)x=(7/8) | | 4a=0.52 | | -4(2n-3)= | | 25h+10= | | 2y+15=5y-10 | | L=200x | | c=3/2(k-21) | | c/2.5=-1 | | -3=p-9 | | p+3=3 |