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1/3(9x+12)+4=13x
We move all terms to the left:
1/3(9x+12)+4-(13x)=0
Domain of the equation: 3(9x+12)!=0We add all the numbers together, and all the variables
x∈R
-13x+1/3(9x+12)+4=0
We multiply all the terms by the denominator
-13x*3(9x+12)+4*3(9x+12)+1=0
Wy multiply elements
-39x^2(9+12x(9+1=0
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