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1/3(9x+12)+4x+6=x
We move all terms to the left:
1/3(9x+12)+4x+6-(x)=0
Domain of the equation: 3(9x+12)!=0We add all the numbers together, and all the variables
x∈R
3x+1/3(9x+12)+6=0
We multiply all the terms by the denominator
3x*3(9x+12)+6*3(9x+12)+1=0
Wy multiply elements
9x^2(9+18x(9+1=0
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