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1/3(9x+12)+5x=3
We move all terms to the left:
1/3(9x+12)+5x-(3)=0
Domain of the equation: 3(9x+12)!=0We add all the numbers together, and all the variables
x∈R
5x+1/3(9x+12)-3=0
We multiply all the terms by the denominator
5x*3(9x+12)-3*3(9x+12)+1=0
Wy multiply elements
15x^2(9-9x(9+1=0
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