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1/3(9x+12)=-2x=-1
We move all terms to the left:
1/3(9x+12)-(-2x)=0
Domain of the equation: 3(9x+12)!=0We get rid of parentheses
x∈R
1/3(9x+12)+2x=0
We multiply all the terms by the denominator
2x*3(9x+12)+1=0
Wy multiply elements
6x^2(9+1=0
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