1/3(9x+27)-7=1/2(2x+54)

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Solution for 1/3(9x+27)-7=1/2(2x+54) equation: 



1/3(9x+27)-7=1/2(2x+54)

We move all terms to the left:

1/3(9x+27)-7-(1/2(2x+54))=0



Domain of the equation: 3(9x+27)!=0

x∈R





Domain of the equation: 2(2x+54))!=0

x∈R



We calculate fractions


(2x2/(3(9x+27)*2(2x+54)))+(-3x9/(3(9x+27)*2(2x+54)))-7=0



We calculate terms in parentheses: +(2x2/(3(9x+27)*2(2x+54))), so:

2x2/(3(9x+27)*2(2x+54))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-3x9/(3(9x+27)*2(2x+54))), so:

-3x9/(3(9x+27)*2(2x+54))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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