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1/3(9x+3)=3x+1*
We move all terms to the left:
1/3(9x+3)-(3x+1*)=0
Domain of the equation: 3(9x+3)!=0We add all the numbers together, and all the variables
x∈R
1/3(9x+3)-(+3x)=0
We get rid of parentheses
1/3(9x+3)-3x=0
We multiply all the terms by the denominator
-3x*3(9x+3)+1=0
Wy multiply elements
-9x^2(9+1=0
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