1/3(9x+3)=3x+9

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Solution for 1/3(9x+3)=3x+9 equation: 



1/3(9x+3)=3x+9

We move all terms to the left:

1/3(9x+3)-(3x+9)=0



Domain of the equation: 3(9x+3)!=0

x∈R



We get rid of parentheses

1/3(9x+3)-3x-9=0

We multiply all the terms by the denominator


-3x*3(9x+3)-9*3(9x+3)+1=0

Wy multiply elements

-9x^2(9-27x(9+1=0

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