1/3(9x+3)=6x-5

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Solution for 1/3(9x+3)=6x-5 equation: 



1/3(9x+3)=6x-5

We move all terms to the left:

1/3(9x+3)-(6x-5)=0



Domain of the equation: 3(9x+3)!=0

x∈R



We get rid of parentheses

1/3(9x+3)-6x+5=0

We multiply all the terms by the denominator


-6x*3(9x+3)+5*3(9x+3)+1=0

Wy multiply elements

-18x^2(9+15x(9+1=0

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