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1/3(9x+3)=x+1
We move all terms to the left:
1/3(9x+3)-(x+1)=0
Domain of the equation: 3(9x+3)!=0We get rid of parentheses
x∈R
1/3(9x+3)-x-1=0
We multiply all the terms by the denominator
-x*3(9x+3)-1*3(9x+3)+1=0
Wy multiply elements
-3x^2(9-3x(9+1=0
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