1/3(9x+42)5x=70

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Solution for 1/3(9x+42)5x=70 equation: 



1/3(9x+42)5x=70

We move all terms to the left:

1/3(9x+42)5x-(70)=0



Domain of the equation: 3(9x+42)5x!=0

x∈R



We multiply all the terms by the denominator


-70*3(9x+42)5x+1=0

Wy multiply elements

-210x(9+1=0

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