1/3(9x+42)5x=70

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Solution for 1/3(9x+42)5x=70 equation:



1/3(9x+42)5x=70
We move all terms to the left:
1/3(9x+42)5x-(70)=0
Domain of the equation: 3(9x+42)5x!=0
x∈R
We multiply all the terms by the denominator
-70*3(9x+42)5x+1=0
Wy multiply elements
-210x(9+1=0

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