1/3(9x-12)+6=-10

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Solution for 1/3(9x-12)+6=-10 equation: 



1/3(9x-12)+6=-10

We move all terms to the left:

1/3(9x-12)+6-(-10)=0



Domain of the equation: 3(9x-12)!=0

x∈R



We add all the numbers together, and all the variables

1/3(9x-12)+16=0

We multiply all the terms by the denominator


16*3(9x-12)+1=0

Wy multiply elements

48x(9+1=0

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