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1/3(9x-12)-6x+15=-19
We move all terms to the left:
1/3(9x-12)-6x+15-(-19)=0
Domain of the equation: 3(9x-12)!=0We add all the numbers together, and all the variables
x∈R
-6x+1/3(9x-12)+34=0
We multiply all the terms by the denominator
-6x*3(9x-12)+34*3(9x-12)+1=0
Wy multiply elements
-18x^2(9+102x(9+1=0
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