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1/3(9x-12)=5x+6
We move all terms to the left:
1/3(9x-12)-(5x+6)=0
Domain of the equation: 3(9x-12)!=0We get rid of parentheses
x∈R
1/3(9x-12)-5x-6=0
We multiply all the terms by the denominator
-5x*3(9x-12)-6*3(9x-12)+1=0
Wy multiply elements
-15x^2(9-18x(9+1=0
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