1/3(9x-15)=1/4(20x-12)

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Solution for 1/3(9x-15)=1/4(20x-12) equation: 



1/3(9x-15)=1/4(20x-12)

We move all terms to the left:

1/3(9x-15)-(1/4(20x-12))=0



Domain of the equation: 3(9x-15)!=0

x∈R





Domain of the equation: 4(20x-12))!=0

x∈R



We calculate fractions


(4x2/(3(9x-15)*4(20x-12)))+(-3x9/(3(9x-15)*4(20x-12)))=0



We calculate terms in parentheses: +(4x2/(3(9x-15)*4(20x-12))), so:

4x2/(3(9x-15)*4(20x-12))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-3x9/(3(9x-15)*4(20x-12))), so:

-3x9/(3(9x-15)*4(20x-12))

We multiply all the terms by the denominator


-3x9

We add all the numbers together, and all the variables

-3x^9

We do not support expression: x^9

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