1/3(9x-15)=7/5(20x-5)

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Solution for 1/3(9x-15)=7/5(20x-5) equation: 



1/3(9x-15)=7/5(20x-5)

We move all terms to the left:

1/3(9x-15)-(7/5(20x-5))=0



Domain of the equation: 3(9x-15)!=0

x∈R





Domain of the equation: 5(20x-5))!=0

x∈R



We calculate fractions


(5x2/(3(9x-15)*5(20x-5)))+(-21x9/(3(9x-15)*5(20x-5)))=0



We calculate terms in parentheses: +(5x2/(3(9x-15)*5(20x-5))), so:

5x2/(3(9x-15)*5(20x-5))

We multiply all the terms by the denominator


5x2

We add all the numbers together, and all the variables

5x^2

Back to the equation:

+(5x^2)





We calculate terms in parentheses: +(-21x9/(3(9x-15)*5(20x-5))), so:

-21x9/(3(9x-15)*5(20x-5))

We multiply all the terms by the denominator


-21x9

We add all the numbers together, and all the variables

-21x^9

We do not support expression: x^9

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