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1/3(9x-18)=2x-3+x-3
We move all terms to the left:
1/3(9x-18)-(2x-3+x-3)=0
Domain of the equation: 3(9x-18)!=0We add all the numbers together, and all the variables
x∈R
1/3(9x-18)-(3x-6)=0
We get rid of parentheses
1/3(9x-18)-3x+6=0
We multiply all the terms by the denominator
-3x*3(9x-18)+6*3(9x-18)+1=0
Wy multiply elements
-9x^2(9+18x(9+1=0
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