1/3(9x-18)=2x-3+x-3

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Solution for 1/3(9x-18)=2x-3+x-3 equation: 



1/3(9x-18)=2x-3+x-3

We move all terms to the left:

1/3(9x-18)-(2x-3+x-3)=0



Domain of the equation: 3(9x-18)!=0

x∈R



We add all the numbers together, and all the variables

1/3(9x-18)-(3x-6)=0

We get rid of parentheses

1/3(9x-18)-3x+6=0

We multiply all the terms by the denominator


-3x*3(9x-18)+6*3(9x-18)+1=0

Wy multiply elements

-9x^2(9+18x(9+1=0

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