1/3(9x-3)=15x-4-10x+7

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Solution for 1/3(9x-3)=15x-4-10x+7 equation: 



1/3(9x-3)=15x-4-10x+7

We move all terms to the left:

1/3(9x-3)-(15x-4-10x+7)=0



Domain of the equation: 3(9x-3)!=0

x∈R



We add all the numbers together, and all the variables

1/3(9x-3)-(5x+3)=0

We get rid of parentheses

1/3(9x-3)-5x-3=0

We multiply all the terms by the denominator


-5x*3(9x-3)-3*3(9x-3)+1=0

Wy multiply elements

-15x^2(9-9x(9+1=0

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