1/3(9x-6)+12=1/4(16x+8)-4

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Solution for 1/3(9x-6)+12=1/4(16x+8)-4 equation: 



1/3(9x-6)+12=1/4(16x+8)-4

We move all terms to the left:

1/3(9x-6)+12-(1/4(16x+8)-4)=0



Domain of the equation: 3(9x-6)!=0

x∈R





Domain of the equation: 4(16x+8)-4)!=0

x∈R



We calculate fractions


(4x1/(3(9x-6)*4(16x+8))+(-3x9/(3(9x-6)*4(16x+8))+12=0

We can not solve this equation

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