1/3(b+2)=1/4b+8

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Solution for 1/3(b+2)=1/4b+8 equation: 



1/3(b+2)=1/4b+8

We move all terms to the left:

1/3(b+2)-(1/4b+8)=0



Domain of the equation: 3(b+2)!=0

b∈R





Domain of the equation: 4b+8)!=0

b∈R



We get rid of parentheses

1/3(b+2)-1/4b-8=0

We calculate fractions


4b/(12b^2+24b)+(-3bb/(12b^2+24b)-8=0

We calculate fractions

We do not support ebpression: b^3

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