1/3(b+6)=1/4b=8

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Solution for 1/3(b+6)=1/4b=8 equation: 



1/3(b+6)=1/4b=8

We move all terms to the left:

1/3(b+6)-(1/4b)=0



Domain of the equation: 3(b+6)!=0

b∈R





Domain of the equation: 4b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

1/3(b+6)-(+1/4b)=0

We get rid of parentheses

1/3(b+6)-1/4b=0

We calculate fractions


4b/(12b^2+72b)+(-3bb/(12b^2+72b)=0



We calculate terms in parentheses: +(-3bb/(12b^2+72b), so:

-3bb/(12b^2+72b

We multiply all the terms by the denominator


-3bb

Back to the equation:

+(-3bb)



We get rid of parentheses

4b/(12b^2+72b)-3bb=0

We multiply all the terms by the denominator


4b-3bb*(12b^2+72b)=0

We multiply parentheses

-36b^3-216b^2+4b=0

We do not support ebpression: b^3

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