1/3(b-9)b+a

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Solution for 1/3(b-9)b+a equation: 


x in (-oo:+oo)

(1/3)*b*(b-9)+a = 0

1/3*b*(b-9)+a = 0

1/3*b*(b-9)+a = 0

a+1/3*b^2-3*b = 0

a+1/3*b^2-3*b = 0

x belongs to the empty set

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