1/3(c+1)=1/6(c-5)

Solution for 1/3(c+1)=1/6(c-5) equation:

1/3(c+1)=1/6(c-5)

We move all terms to the left:

1/3(c+1)-(1/6(c-5))=0


Domain of the equation: 3(c+1)!=0

c∈R



Domain of the equation: 6(c-5))!=0

c∈R


We calculate fractions


(6cc/(3(c+1)*6(c-5)))+(-3cc/(3(c+1)*6(c-5)))=0


We calculate terms in parentheses: +(6cc/(3(c+1)*6(c-5))), so:

6cc/(3(c+1)*6(c-5))

We multiply all the terms by the denominator


6cc

Back to the equation:

+(6cc)



We calculate terms in parentheses: +(-3cc/(3(c+1)*6(c-5))), so:

-3cc/(3(c+1)*6(c-5))

We multiply all the terms by the denominator


-3cc

Back to the equation:

+(-3cc)


We get rid of parentheses

6cc-3cc=0