1/3(c-6)=12

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Solution for 1/3(c-6)=12 equation: 



1/3(c-6)=12

We move all terms to the left:

1/3(c-6)-(12)=0



Domain of the equation: 3(c-6)!=0

c∈R



We multiply all the terms by the denominator


-12*3(c-6)+1=0

Wy multiply elements

-36c(c+1=0

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