1/3(d-4)-3/2(5d-3)=7/12

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Solution for 1/3(d-4)-3/2(5d-3)=7/12 equation:


d in (-oo:+oo)

(1/3)*(d-4)-((3/2)*(5*d-3)) = 7/12 // - 7/12

(1/3)*(d-4)-((3/2)*(5*d-3))-(7/12) = 0

(1/3)*(d-4)+(-3/2)*(5*d-3)-7/12 = 0

1/3*(d-4)-3/2*(5*d-3)-7/12 = 0

(1/3*12*(d-4))/12+(-3/2*12*(5*d-3))/12-7/12 = 0

1/3*12*(d-4)-3/2*12*(5*d-3)-7 = 0

38-86*d-7 = 0

31-86*d = 0

(31-86*d)/12 = 0

(31-86*d)/12 = 0 // * 12

31-86*d = 0

31-86*d = 0 // - 31

-86*d = -31 // : -86

d = -31/(-86)

d = 31/86

d = 31/86

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