1/3(d-4)-7/2(3d-5)=5/12

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Solution for 1/3(d-4)-7/2(3d-5)=5/12 equation: 



1/3(d-4)-7/2(3d-5)=5/12

We move all terms to the left:

1/3(d-4)-7/2(3d-5)-(5/12)=0



Domain of the equation: 3(d-4)!=0

d∈R





Domain of the equation: 2(3d-5)!=0

d∈R



We add all the numbers together, and all the variables

1/3(d-4)-7/2(3d-5)-(+5/12)=0

We get rid of parentheses

1/3(d-4)-7/2(3d-5)-5/12=0

We calculate fractions


(24d3/(3(d-4)*2(3d-5)*12)+(-252dd/(3(d-4)*2(3d-5)*12)+(-30d^2d/(3(d-4)*2(3d-5)*12)=0



We calculate terms in parentheses: +(24d3/(3(d-4)*2(3d-5)*12)+(-252dd/(3(d-4)*2(3d-5)*12)+(-30d^2d/(3(d-4)*2(3d-5)*12), so:

24d3/(3(d-4)*2(3d-5)*12)+(-252dd/(3(d-4)*2(3d-5)*12)+(-30d^2d/(3(d-4)*2(3d-5)*12

We can not solve this equation

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