1/3(d-7)-7/2(5d-1)=7/12

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Solution for 1/3(d-7)-7/2(5d-1)=7/12 equation:


d in (-oo:+oo)

(1/3)*(d-7)-((7/2)*(5*d-1)) = 7/12 // - 7/12

(1/3)*(d-7)-((7/2)*(5*d-1))-(7/12) = 0

(1/3)*(d-7)+(-7/2)*(5*d-1)-7/12 = 0

1/3*(d-7)-7/2*(5*d-1)-7/12 = 0

(1/3*12*(d-7))/12+(-7/2*12*(5*d-1))/12-7/12 = 0

1/3*12*(d-7)-7/2*12*(5*d-1)-7 = 0

14-206*d-7 = 0

7-206*d = 0

(7-206*d)/12 = 0

(7-206*d)/12 = 0 // * 12

7-206*d = 0

7-206*d = 0 // - 7

-206*d = -7 // : -206

d = -7/(-206)

d = 7/206

d = 7/206

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