1/3(f+5)=10

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Solution for 1/3(f+5)=10 equation: 



1/3(f+5)=10

We move all terms to the left:

1/3(f+5)-(10)=0



Domain of the equation: 3(f+5)!=0

f∈R



We multiply all the terms by the denominator


-10*3(f+5)+1=0

Wy multiply elements

-30f(f+1=0

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