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1/3(m+4)+6=1/4(3m-1)-2
We move all terms to the left:
1/3(m+4)+6-(1/4(3m-1)-2)=0
Domain of the equation: 3(m+4)!=0
m∈R
Domain of the equation: 4(3m-1)-2)!=0We calculate fractions
m∈R
(4m3/(3(m+4)*4(3m-1))+(-3mm/(3(m+4)*4(3m-1))+6=0
We can not solve this equation
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