1/3(m-2)=7/6(m+5)-5/3m

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Solution for 1/3(m-2)=7/6(m+5)-5/3m equation: 


m in (-oo:+oo)

(1/3)*(m-2) = (7/6)*(m+5)-((5/3)*m) // - (7/6)*(m+5)-((5/3)*m)

(1/3)*(m-2)-((7/6)*(m+5))+(5/3)*m = 0

(1/3)*(m-2)+(-7/6)*(m+5)+(5/3)*m = 0

1/3*(m-2)-7/6*(m+5)+(5*m)/3 = 0

(1/3*3*(m-2))/3+(-7/6*3*(m+5))/3+(5*m)/3 = 0

1/3*3*(m-2)-7/6*3*(m+5)+5*m = 0

5*m-5/2*m-39/2 = 0

5/2*m-39/2 = 0

(5/2*m-39/2)/3 = 0

(5/2*m-39/2)/3 = 0 // * 3

5/2*m-39/2 = 0

5/2*m-39/2 = 0 // + 39/2

5/2*m = 39/2 // : 5/2

m = 39/2/5/2

m = 39/5

m = 39/5

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