1/3(n+3)=n-3

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Solution for 1/3(n+3)=n-3 equation: 



1/3(n+3)=n-3

We move all terms to the left:

1/3(n+3)-(n-3)=0



Domain of the equation: 3(n+3)!=0

n∈R



We get rid of parentheses

1/3(n+3)-n+3=0

We multiply all the terms by the denominator


-n*3(n+3)+3*3(n+3)+1=0

Wy multiply elements

-3n^2(n+9n(n+1=0

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