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1/3(n+8)=1/2(4n+1)
We move all terms to the left:
1/3(n+8)-(1/2(4n+1))=0
Domain of the equation: 3(n+8)!=0
n∈R
Domain of the equation: 2(4n+1))!=0We calculate fractions
n∈R
(2n4/(3(n+8)*2(4n+1)))+(-3nn/(3(n+8)*2(4n+1)))=0
We calculate terms in parentheses: +(2n4/(3(n+8)*2(4n+1))), so:
2n4/(3(n+8)*2(4n+1))
We multiply all the terms by the denominator
2n4
We add all the numbers together, and all the variables
2n^4
We do not support enpression: n^4
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