1/3(n-4)=-2n+6

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Solution for 1/3(n-4)=-2n+6 equation: 



1/3(n-4)=-2n+6

We move all terms to the left:

1/3(n-4)-(-2n+6)=0



Domain of the equation: 3(n-4)!=0

n∈R



We get rid of parentheses

1/3(n-4)+2n-6=0

We multiply all the terms by the denominator


2n*3(n-4)-6*3(n-4)+1=0

Wy multiply elements

6n^2(n-18n(n+1=0

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