1/3(n-7)=5/3(n+(-5))

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Solution for 1/3(n-7)=5/3(n+(-5)) equation: 



1/3(n-7)=5/3(n+(-5))

We move all terms to the left:

1/3(n-7)-(5/3(n+(-5)))=0



Domain of the equation: 3(n-7)!=0

n∈R





Domain of the equation: 3(n+(-5)))!=0

n∈R



We calculate fractions


(3nn/(3(n-7)*3(n+(-5))))+(-15nn/(3(n-7)*3(n+(-5))))=0



We calculate terms in parentheses: +(3nn/(3(n-7)*3(n+(-5)))), so:

3nn/(3(n-7)*3(n+(-5)))

We multiply all the terms by the denominator


3nn

Back to the equation:

+(3nn)





We calculate terms in parentheses: +(-15nn/(3(n-7)*3(n+(-5)))), so:

-15nn/(3(n-7)*3(n+(-5)))

We multiply all the terms by the denominator


-15nn

Back to the equation:

+(-15nn)



We get rid of parentheses

3nn-15nn=0

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