1/3(r+6)=1/7(r+8)

Solution for 1/3(r+6)=1/7(r+8) equation:

1/3(r+6)=1/7(r+8)

We move all terms to the left:

1/3(r+6)-(1/7(r+8))=0


Domain of the equation: 3(r+6)!=0

r∈R



Domain of the equation: 7(r+8))!=0

r∈R


We calculate fractions


(7rr/(3(r+6)*7(r+8)))+(-3rr/(3(r+6)*7(r+8)))=0


We calculate terms in parentheses: +(7rr/(3(r+6)*7(r+8))), so:

7rr/(3(r+6)*7(r+8))

We multiply all the terms by the denominator


7rr

Back to the equation:

+(7rr)



We calculate terms in parentheses: +(-3rr/(3(r+6)*7(r+8))), so:

-3rr/(3(r+6)*7(r+8))

We multiply all the terms by the denominator


-3rr

Back to the equation:

+(-3rr)


We get rid of parentheses

7rr-3rr=0