1/3(t+6)-10=-3t2

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Solution for 1/3(t+6)-10=-3t2 equation: 



1/3(t+6)-10=-3t^2

We move all terms to the left:

1/3(t+6)-10-(-3t^2)=0



Domain of the equation: 3(t+6)!=0

t∈R



We get rid of parentheses

3t^2+1/3(t+6)-10=0

We multiply all the terms by the denominator


3t^2*3(t+6)-10*3(t+6)+1=0

Wy multiply elements

9t^3(t-30t(t+1=0

We do not support etpression: t^3(t

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