1/3(w+4)-6=2/3(5-w)

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Solution for 1/3(w+4)-6=2/3(5-w) equation: 



1/3(w+4)-6=2/3(5-w)

We move all terms to the left:

1/3(w+4)-6-(2/3(5-w))=0



Domain of the equation: 3(w+4)!=0

w∈R





Domain of the equation: 3(5-w))!=0

w∈R



We add all the numbers together, and all the variables

1/3(w+4)-(2/3(-1w+5))-6=0

We calculate fractions


(3w(-)/(3(w+4)*3(-1w+5)))+(-6ww/(3(w+4)*3(-1w+5)))-6=0



We calculate terms in parentheses: +(3w(-)/(3(w+4)*3(-1w+5))), so:

3w(-)/(3(w+4)*3(-1w+5))

We add all the numbers together, and all the variables

3w0/(3(w+4)*3(-1w+5))

We multiply all the terms by the denominator


3w0

We add all the numbers together, and all the variables

3w

Back to the equation:

+(3w)





We calculate terms in parentheses: +(-6ww/(3(w+4)*3(-1w+5))), so:

-6ww/(3(w+4)*3(-1w+5))

We multiply all the terms by the denominator


-6ww

Back to the equation:

+(-6ww)



We get rid of parentheses

3w-6ww-6=0

We move all terms containing w to the left, all other terms to the right

3w-6ww=6

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