1/3(x+1)+2=1/6(3x-5)

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Solution for 1/3(x+1)+2=1/6(3x-5) equation: 



1/3(x+1)+2=1/6(3x-5)

We move all terms to the left:

1/3(x+1)+2-(1/6(3x-5))=0



Domain of the equation: 3(x+1)!=0

x∈R





Domain of the equation: 6(3x-5))!=0

x∈R



We calculate fractions


(6x3/(3(x+1)*6(3x-5)))+(-3xx/(3(x+1)*6(3x-5)))+2=0



We calculate terms in parentheses: +(6x3/(3(x+1)*6(3x-5))), so:

6x3/(3(x+1)*6(3x-5))

We multiply all the terms by the denominator


6x3

We add all the numbers together, and all the variables

6x^3

We do not support expression: x^3

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