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(1/3)*(x+1) = (1/6)*(3*x-5) // - (1/6)*(3*x-5)
(1/3)*(x+1)-((1/6)*(3*x-5)) = 0
(1/3)*(x+1)+(-1/6)*(3*x-5) = 0
1/3*(x+1)-1/6*(3*x-5) = 0
1/3*(x+1)-1/6*(3*x-5) = 0
7/6-1/6*x = 0
7/6-1/6*x = 0
7/6-1/6*x = 0 // - 7/6
-1/6*x = -7/6 // : -1/6
x = -7/6/(-1/6)
x = 7
x = 7
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