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1/3(x+1)=2/3-5x
We move all terms to the left:
1/3(x+1)-(2/3-5x)=0
Domain of the equation: 3(x+1)!=0
x∈R
Domain of the equation: 3-5x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-5x)!=-3
x!=-3/1
x!=-3
x∈R
1/3(x+1)-(-5x+2/3)=0
We get rid of parentheses
1/3(x+1)+5x-2/3=0
We calculate fractions
5x=0
x=0/5
x=0
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