1/3(x+2)=1/3x=2/3

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Solution for 1/3(x+2)=1/3x=2/3 equation: 



1/3(x+2)=1/3x=2/3

We move all terms to the left:

1/3(x+2)-(1/3x)=0



Domain of the equation: 3(x+2)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/3(x+2)-(+1/3x)=0

We get rid of parentheses

1/3(x+2)-1/3x=0

We calculate fractions


3x/(9x^2+18x)+(-3xx/(9x^2+18x)=0



We calculate terms in parentheses: +(-3xx/(9x^2+18x), so:

-3xx/(9x^2+18x

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)



We get rid of parentheses

3x/(9x^2+18x)-3xx=0

We multiply all the terms by the denominator


3x-3xx*(9x^2+18x)=0

We multiply parentheses

-27x^3-54x^2+3x=0

We do not support expression: x^3

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