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x in (-oo:+oo)
(1/3)*(x+2) = (1/9)*(3*x-4) // - (1/9)*(3*x-4)
(1/3)*(x+2)-((1/9)*(3*x-4)) = 0
(1/3)*(x+2)+(-1/9)*(3*x-4) = 0
1/3*(x+2)-1/9*(3*x-4) = 0
1/3*(x+2)-1/9*(3*x-4) = 0
10/9 = 0
10/9 = 0
10/9 = 0 // * 9
10 = 0
x belongs to the empty set
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