1/3(x+3)-4x=3/2(2x-7)

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Solution for 1/3(x+3)-4x=3/2(2x-7) equation: 



1/3(x+3)-4x=3/2(2x-7)

We move all terms to the left:

1/3(x+3)-4x-(3/2(2x-7))=0



Domain of the equation: 3(x+3)!=0

x∈R





Domain of the equation: 2(2x-7))!=0

x∈R



We add all the numbers together, and all the variables

-4x+1/3(x+3)-(3/2(2x-7))=0

We calculate fractions


-4x+(2x2/(3(x+3)*2(2x-7)))+(-9xx/(3(x+3)*2(2x-7)))=0



We calculate terms in parentheses: +(2x2/(3(x+3)*2(2x-7))), so:

2x2/(3(x+3)*2(2x-7))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-9xx/(3(x+3)*2(2x-7))), so:

-9xx/(3(x+3)*2(2x-7))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



determiningTheFunctionDomain
2x^2-4x+(-9xx)=0

We get rid of parentheses

2x^2-4x-9xx=0

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