1/3(x+4)=20.X=48

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Solution for 1/3(x+4)=20.X=48 equation: 



1/3(x+4)=20.x=48

We move all terms to the left:

1/3(x+4)-(20.x)=0



Domain of the equation: 3(x+4)!=0

x∈R



We add all the numbers together, and all the variables

1/3(x+4)-(+20.x)=0

We get rid of parentheses

1/3(x+4)-20.x=0

We multiply all the terms by the denominator


-(20.x)*3(x+4)+1=0

We add all the numbers together, and all the variables

-(+20.x)*3(x+4)+1=0

We move all terms containing x to the left, all other terms to the right

-(+20.x)*3(x+4)=-1

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