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1/3(x+4)=3+x
We move all terms to the left:
1/3(x+4)-(3+x)=0
Domain of the equation: 3(x+4)!=0We add all the numbers together, and all the variables
x∈R
1/3(x+4)-(x+3)=0
We get rid of parentheses
1/3(x+4)-x-3=0
We multiply all the terms by the denominator
-x*3(x+4)-3*3(x+4)+1=0
Wy multiply elements
-3x^2(x-9x(x+1=0
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