1/3(x+6)=1/2(x-3)*

Solution for 1/3(x+6)=1/2(x-3)* equation:

1/3(x+6)=1/2(x-3)*

We move all terms to the left:

1/3(x+6)-(1/2(x-3)*)=0


Domain of the equation: 3(x+6)!=0

x∈R



Domain of the equation: 2(x-3)*)!=0

x∈R


We calculate fractions


(2x^2x/(3(x+6)*2(x-3)*))+(-3xx/(3(x+6)*2(x-3)*))=0


We calculate terms in parentheses: +(2x^2x/(3(x+6)*2(x-3)*)), so:

2x^2x/(3(x+6)*2(x-3)*)

We multiply all the terms by the denominator


2x^2x

Back to the equation:

+(2x^2x)



We calculate terms in parentheses: +(-3xx/(3(x+6)*2(x-3)*)), so:

-3xx/(3(x+6)*2(x-3)*)

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2x^2x-3xx=0